Games:Puzzles in Lone Wolf (books 1 to 12)
From Stiki
This page gives solution to puzzles in Lone Wolf books 1 to 12 (the Kai and Magnakai series).
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Lone Wolf 5: Shadow on the Sand
Tipasa's code
Project Aon: Lone Wolf, Book 5 (Shadow on the Sand), Section 331
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Reading the supplementary information that is found on the page with the map of Vassagonia gives the data required for the puzzle: Project Aon: Lone Wolf, Book 5 (Shadow on the Sand), The Empire of Vassagonia |
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The solution to the problem is therefore 373 (concatenating the numbers): Project Aon: Lone Wolf, Book 5 (Shadow on the Sand), Section 373 |
Lone Wolf 7: Castle Death
Wall plaque
Project Aon: Lone Wolf, Book 7 (Castle Death), Section 11
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If you use Divination or do not have Pathsmanship, the possible answers are reduced down to 3, 9, 13, or 33. If you use Pathsmanship, the method of solving the puzzle is revealed: Project Aon: Lone Wolf, Book 7 (Castle Death), Section 306 |
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Defining the triangle size as the number of cells along each edge of the triangle, the count of triangles is as follows:
The total number of triangles is therefore 13: Project Aon: Lone Wolf, Book 7 (Castle Death), Section 13 |
Zakhan's riddle
Project Aon: Lone Wolf, Book 7 (Castle Death), Section 100
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Define S as the number of sons, and D as the number of daughters. The riddle breaks down into two statements with the following equations: D-1 = S D = 2×(S-1) Substituting D from the second equation into the first gives: 2×(S-1) - 1 = S 2S - 2 - 1 = S 2S - 3 = S S - 3 = 0 S = 3 D = 4 Checking these results, each daughter will have three sisters and three brothers and each son will have four sisters and two brothers, as required. The correct answer is therefore 34 (concatenating the numbers): Project Aon: Lone Wolf, Book 7 (Castle Death), Section 34 |
Lone Wolf 8: The Jungle of Horrors
Old man's riddle
Project Aon: Lone Wolf, Book 8 (The Jungle of Horrors), Section 112
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Define B as the weight of a brick: B = 0.75 + 0.75×B 0.25×B = 0.75 B = 3 Checking this result, three quarters of 3lb gives 2.25lb, plus the additional 0.75lb gives 3lb as required. The correct answer is therefore 3: Project Aon: Lone Wolf, Book 8 (The Jungle of Horrors), Section 3 |
Count Conundrum 1
Project Aon: Lone Wolf, Book 8 (The Jungle of Horrors), Section 126
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Define E as the number of eggs laid by one goose in one day: 1.5 × 1.5 × E = 1.5 1.5 × E = 1 E = 1 / 1.5 E = 2/3 So in eight days, three geese will lay 8*3*E eggs, or 16 eggs. The correct answer is therefore 16: Project Aon: Lone Wolf, Book 8 (The Jungle of Horrors), Section 16 |
Count Conundrum 2
Project Aon: Lone Wolf, Book 8 (The Jungle of Horrors), Section 141
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Working backwards, if the lake is first completely covered after 60 days, twenty-four hours earlier the lake will have been half covered. The correct answer is therefore 59: Project Aon: Lone Wolf, Book 8 (The Jungle of Horrors), Section 59 |
Count Conundrum 3
Project Aon: Lone Wolf, Book 8 (The Jungle of Horrors), Section 338
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Define E as the initial number of eggs that the trader had: ((E/2 - 0.5)/2 - 0.5)/2 - 0.5 = 0 ((E/2 - 0.5)/2 - 0.5)/2 = 0.5 (E/2 - 0.5)/2 - 0.5 = 1 (E/2 - 0.5)/2 = 1.5 E/2 - 0.5 = 3 E/2 = 3.5 E = 7 Checking this result:
The correct answer is therefore 7: Project Aon: Lone Wolf, Book 8 (The Jungle of Horrors), Section 7 |
Lone Wolf 9: The Cauldron of Fear
Khmar 1
Project Aon: Lone Wolf, Book 9 (The Cauldron of Fear), Section 115
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Define D as the current age of the dagger, and L as the current age of Loen. The riddle breaks down into two statements with the following equations: D = (L - D)/2 L = 15 Substituting L from the second equation into the first gives: D = (15 - D)/2 2×D = 15 - D 3×D = 15 D = 5 Checking this result, the dagger was new five years ago at which point Loen would have been 10. This is twice the current age of the dagger as required. The correct answer is therefore 5: Project Aon: Lone Wolf, Book 9 (The Cauldron of Fear), Section 5 |
Khmar 2
Project Aon: Lone Wolf, Book 9 (The Cauldron of Fear), Section 204
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Define J as the current age of Juno, and K as the current age of Khmar. The riddle breaks down into two statements with the following equations: K = 4 × J K+20 = 2 × (J+20) Substituting K from the first equation into the second gives: (4×J) + 20 = 2 × (J+20) 4×J + 20 = 2×J + 40 2×J = 20 J = 10 K = 40 Checking these results:
The correct answer is therefore 50 (adding the two ages together): Project Aon: Lone Wolf, Book 9 (The Cauldron of Fear), Section 50 |
| Puzzles in Lone Wolf |
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| Books 1 to 12 · Books 13 to 16 · Books 17 to 20 · Books 21 to 28 |

